Calculate a User's Reputation

Question

Challenge

Given a user's name (not ID, we have that challenge already), output their current reputation and their ID.

Input

Input will be a single string which is the user's username. You may assume that this user exists.

Output

Output will be two integers to either STDOUT or STDERR which will be the user's reputation and the user's ID. They must be in that specific order and can be output in any reasonable format

Specifics

• The reputation output must not be more than 10 minutes out of date.
• Your program may not throw any errors during normal execution
• Standard loopholes apply (including No URL Shorteners)
• If there is more than one user with that username, you may output the stats of any user with that username. This is also why you must output the ID.
• The reputation to be output is the reputation of the user on PPCG, not the network total score.

The Stack Exchange API site can be found here. You can read the documentation from there.

Answer 1

Bash + JQ, 93 bytes

Rolled back the 87 byte version, as it was not handling multi-user responses correctly.

Golfed

curl "api.stackexchange.com/users?site=codegolf&inname=$1"|zcat|jq ..\|numbers|sed -n 4p\;12p

Will output first user id and reputation on the separate lines.

How It Works ?

1)curl + zcat are used to fetch the JSON formatted API reply

2) jq ..|numbers will unfold JSON recursively, and print all the numeric values, one per line

...
1   35
2   8
3   2
4   3315904
5   1487694154
6   1492702469
7   4565
8   82
9   82
10  60
11  20
12  6275
...

(line numbers were added with nl for illustration purposes only)

3) Next we use sed to lookup the first account_id and reputation, by their absolute row numbers

Test

>./reputation zeppelin
3315904
6275

Answer 2

JavaScript (ES6), 145 139 136 125 123 117 bytes

a=>fetch(`//api.stackexchange.com/users?site=codegolf&filter=!)LgZAmQ6ls0hH&inname=`+a).then(_=>_.text()).then(alert)

Saved 6 bytes thanks to Shaggy and 6 bytes thanks to Cyoce.

I'm not sure if it should output all users with the same name, or just one of them; this code outputs all of them.

f=a=>fetch(`//api.stackexchange.com/users?site=codegolf&filter=!)LgZAmQ6ls0hH&inname=`+a).then(_=>_.text()).then(alert)

f("tom")

Answer 3

Python 2, 178 169 149 Bytes

I'd use requests for this:

from requests import*
a=get("http://api.stackexchange.com/users?site=codegolf&inname="+input()).json()["items"][0]
print a["reputation"],a["user_id"]

Basically, it uses stack's api to fetch the information as JSON and then gets the item "reputation". Additionally, the API featured many extra parameters, I shaved those off as well.

Generous contributions from: carusocomputing, ElPedro, Malivil, Keerthana Prabhakaran

Answer 4

Groovy, 144 156 bytes

{new groovy.json.JsonSlurper().parse(new URL("http://api.stackexchange.com/2.2/users/?site=codegolf&inname=$it")).items.collect{[it.user_id,it.reputation]}}

Anonymous closure.

EDIT: forgot to use import of groovy.json. for JSON Slurper + 14 bytes.

Example output [[UserID, Reputation],...]:

[[20260, 60695], [20469, 21465], [3103, 8856], [41805, 7783], [134, 6829], [42643, 5622], [45268, 4389], [10732, 3976], [32, 3635], [53745, 3392], [10801, 3216], [49362, 2418], [2104, 2160], [3563, 1988], [18280, 1491], [742, 1466], [59487, 1362], [19039, 1330], [56642, 1133], [9522, 951], [34438, 886], [1744, 793], [52661, 778], [18187, 768], [11426, 751], [26850, 711], [178, 637], [29451, 631], [19700, 616], [15862, 601]]

Answer 5

Swift, 225 201 bytes

import Foundation;var f:(String)->Any={return try!JSONSerialization.jsonObject(with:Data(contentsOf:URL(string:"http://api.stackexchange.com/users?site=codegolf&filter=!)LgZAmQ6ls0hH&inname=\($0)")!))}

Un-golfed:

import Foundation

var f:(String) -> [String: Any] = {
    return try! JSONSerialization.jsonObject(with:Data(contentsOf:URL(string:"http://api.stackexchange.com/users?site=codegolf&filter=!)LgZAmQ6ls0hH&inname=\($0)")!)) as! [String:Any]
}

Example output:

["items": <__NSArrayI 0x6180001ffc00>(
{
    reputation = 2820;
    "user_id" = 42295;
},
{
    reputation = 2468;
    "user_id" = 31203;
},
{
    reputation = 2106;
    "user_id" = 2800;
},
{
    reputation = 1479;
    "user_id" = 6689;
},
{
    reputation = 1287;
    "user_id" = 64424;
},
{
    reputation = 1037;
    "user_id" = 64070;
},
{
    reputation = 644;
    "user_id" = 25193;
},
{
    reputation = 641;
    "user_id" = 3171;
},
{
    reputation = 639;
    "user_id" = 743;
},
{
    reputation = 590;
    "user_id" = 33233;
},
{
    reputation = 571;
    "user_id" = 26993;
},
{
    reputation = 563;
    "user_id" = 1730;
},
{
    reputation = 321;
    "user_id" = 18570;
},
{
    reputation = 309;
    "user_id" = 39156;
},
{
    reputation = 291;
    "user_id" = 7880;
},
{
    reputation = 281;
    "user_id" = 25190;
},
{
    reputation = 261;
    "user_id" = 40820;
},
{
    reputation = 231;
    "user_id" = 14154;
},
{
    reputation = 206;
    "user_id" = 2774;
},
{
    reputation = 196;
    "user_id" = 48231;
},
{
    reputation = 181;
    "user_id" = 1230;
},
{
    reputation = 176;
    "user_id" = 64077;
},
{
    reputation = 171;
    "user_id" = 31365;
},
{
    reputation = 171;
    "user_id" = 43455;
},
{
    reputation = 163;
    "user_id" = 21469;
},
{
    reputation = 161;
    "user_id" = 11845;
},
{
    reputation = 157;
    "user_id" = 25181;
},
{
    reputation = 131;
    "user_id" = 263;
},
{
    reputation = 131;
    "user_id" = 3922;
},
{
    reputation = 128;
    "user_id" = 67227;
}
)
]