100 Day Countdown

Question

It is common to start countdowns 100 days prior to an event, probably because of our base 10 system. Examples of this can be found everywhere:

• 100 days until your birthday
• 100 days until the wedding
• 100 days until the election
• 100 days until our graduation
• 100 days until her due date
• 100 days until football season
• 100 days until you get the Fanatic badge

You get the picture. It seems that the 100th day before an event is second place only to the actual event. So for this challenge, I need to know what the date will be in 100 days, so that I can determine what I should start counting down too.

Input

No input

Output

The date 100 days from the current date based on the standard Gregorian Calendar (Make sure to account for leap years). Output is flexible as long as the date format is human read-able (eg 2016-10-8, 10-8-16, [ 2016, 10, 8 ], 10/8/16 12:00:00 AM).

Winning

Code golf: shortest code in bytes

---

Examples

100 days from today (Apr 5th, 2017) is Friday, July 14 2017.

Current                Future
-------                ------
01/01/2001 +100        04/11/2001
01/01/2004 +100        04/10/2004
01/01/1900 +100        04/11/1900
01/01/2000 +100        04/10/2000

07/04/2017 +100        10/12/2017
10/31/2017 +100        02/08/2018
12/25/2017 +100        04/04/2018

08/29/1941 +100        12/07/1941
06/03/2001 +100        09/11/2001

Answer 1

Excel, 10

=NOW()+100

Demonstration

Answer 2

Bash, 17 16 15 14 13 bytes

date -d100day

It turns out the date command takes some pretty flexible input for relative timings. You can also do things like 1 year, 1 week ago, yesterday, etc. It's pretty cool.

-1 byte by realizing that bash does not care about grammar.
-1 byte because the space between 100 and day is unnecessary.
-1 byte because I don't need quotes anymore because I don't have a space in the string.
-1 byte by removing the space after -d (thanks ASCII-only!)

Answer 3

PowerShell, 10 bytes

(date)+1e2

^{Thanks to ConnorLSW for the +1e2 trick.}

It appears that doubles (1e2 is a double) are also added as days.

Previous version, 12 bytes:

(date)+"100"

Apparently you can add strings to dates in PowerShell. The string "100" is converted into a 100 days-TimeSpan.

Answer 4

Mediawiki, 19bytes

{{#time:r|+100day}}

You may try it with wikipedia's sandbox

Answer 5

PHP, 28 bytes

<?=date(Y_m_d,time()+864e4);

human readable version, 35 bytes:

<?=date(Y_m_d,strtotime("100day"));

almost readable, 34 bytes:

<?=date(Y_m_d,strtotime(1e2.day));

-4 bytes if also printing the time is accepted: replace Y_m_d with r or c.

It´s National Holiday in France in 100 days.

Answer 6

Ruby, 16 bytes

p Time.now+864e4

Try it online!

Answer 7

Javascript, 29 26 25 bytes

Saved 3 bytes thanks to @ASCII-only!

Saved 1 byte thanks to @JohanKarlsson

new Date(+new Date+864e7)

document.body.innerHTML=new Date(+new Date+864e7)

Answer 8

SQL (PostgreSQL), 19 Bytes

SELECT now()+'100d'

Answer 9

Vim, 27 bytes

:r!date "+\%F" -d"+100 day"

try it online!

Edit: Removed unnecessary space char.

Answer 10

MATL, 9 bytes

Z'100+1XO

Output format is 15-Jul-2017 (which I find most readable). Change 1XO to 2XO to get the format used in the examples, 07/15/17.

Try it online!

Explanation

Z'      % Push current date and time as a serial date number
100+    % Add 100
1XO     % Convert to string with format 'dd-mmm-yyyy'. Implicitly display

Answer 11

SQL (Microsoft), 35 31 bytes

SELECT DATEADD(D,100,GETDATE())

Answer 12

Mathematica, 26 21 bytes

-5 bytes thanks to @KiranLinsuain!

Today+Quantity@"100d"

If including the time is permitted, then we can save 2 bytes:

Now+Quantity@"100d"

Answer 13

C#, 103 97 bytes

Thanks to raznagul for saving 6 bytes!

using System;class P{static void Main(){Console.Write(DateTime.Now.AddDays(100).ToString("d"));}}

Full program which reads the current date, adds 100 days and displays the result in M/d/YYYY format.

You can change the date format by adding a few more bytes:

using System;class P{static void Main(){Console.Write(DateTime.Now.AddDays(100).ToString("d-M-yyyy"));}}

---

To eliminate boilerplate code - C# isn't exactly known to be very compact - an anonymous function can be used:

C# lambda, 49 43 bytes

()=>DateTime.Now.AddDays(100).ToString("d")

Full program:

using System;

class P
{
    static void Main()
    {
        Func<string> f = 
        ()=>DateTime.Now.AddDays(100).ToString("d");

        Console.WriteLine(f());
    }
}

Answer 14

Java 8, 77, 61 bytes

()->System.out.print(java.time.LocalDate.now().plusDays(100))

Try it online!

Answer 15

Noodel, 8 bytes

]5@LaƇ⁺ƈ

Try it:)

---

How it works

]5@LaƇ⁺ƈ
]5@La    # The string "]5@La" gets pushed onto the stack which in base 98 represents 8,640,000,000.
     Ƈ   # Pushes an integer that represents the current time where highest resolution is milliseconds.
      ⁺  # Add the time and the string which will be interpreted as 8,640,000,000ms.
       ƈ # Convert the integer to human readable time.
         # Implicitly output to the screen.

<div id="noodel" code="]5@LaƇ⁺ƈ" input="" cols="80" rows="2"/>

<script src="https://tkellehe.github.io/noodel/noodel-latest.js"></script>
<script src="https://tkellehe.github.io/noodel/ppcg.min.js"></script>

Answer 16

C, 87 46 44 bytes

saved 2 bytes thanks to Albert Renshaw

f(){time_t t=time(0)+864e4;puts(ctime(&t));}

I realized the output is flexible enough to allow for day of week and time, so there's no need to use localtime or the tm structure at all.

Old answer

f(){time_t t=time(0)+8640000;char b[9];strftime(b,9,"%d-%m-%y",localtime(&t));puts(b);}

Based on Khaled.K's answer, but instead of messing with the tm structure, adds the number of seconds equivalent to 100 days directly to the time_t value. It also prints only the date, without time or day of week.

As it should happen on a golfed program, some ugly warnings are generated on compilation.

Try it online!

Ungolfed:

f(){
    // Current time + 100 days
    time_t t=time(0)+8640000;
    // Buffer for printing formatted time
    char b[9];
    // Print the time in format dd-mm-yy to buffer
    strftime(b,9,"%d-%m-%y",localtime(&t));
    // print buffer
    puts(b);
}

Answer 17

JavaScript, 42 bytes

(d=new Date()).setDate(d.getDate()+100)&&d

setInterval(_=>document.body.innerHTML=(d=new Date()).setDate(d.getDate()+100)&&d,1000)

Answer 18

IBM/Lotus Notes Formula, 29 bytes

@Adjust(@Today;0;0;100;0;0;0)

Unfortunately @Adjust requires the trailing 0's for the missing hh:mm:ss.

If we were allowed to display the time as well then changing @Today to @Now would save 2 bytes for 27.

Answer 19

JavaScript (ES6), 44 bytes

_=>new Date(Date.now()+864e7).toDateString()

25 bytes if returning a date with the time is acceptable:

_=>Date(Date.now()+864e7)

Answer 20

30 bytes

Mysql!

select NOW()+INTERVAL 100 DAY;

SQLite

SELECT date('now','+100 day');

Answer 21

C, 120 113 bytes

#include <time.h>
f(){time_t t=time(0);struct tm*tm=localtime(&t);tm->tm_mday+=100;t=mktime(tm);printf("%s",ctime(&t));}

Live Demo

#include <stdio.h>
#include <time.h>

void PrintDatePlus100days()
{
    // obtain current time
    time_t t = time( 0 );

    // convert to datetime struct
    struct tm *tm = localtime( &t );

    // add 100 days
    tm->tm_mday += 100;

    // convert to time_t
    t = mktime( tm );

    // print time in readable format
    puts( ctime( &t ) );
}

Answer 22

F# (53 bytes)

printf"%s"(DateTime.Now.AddDays(100.0).ToString("d"))

Answer 23

Swift 3, 39 bytes

print(Date(timeIntervalSinceNow:864E4))

Answer 24

R (REPL), 14 bytes

Sys.Date()+100

Try it on Ideone.

Answer 25

PowerShell, 23

(get-date).adddays(100)

This is my first ever try, so please give me constructive feedback. Thanks!

Answer 26

Python, 63 bytes

from datetime import*
print(datetime.now()+timedelta(days=100))

Very simple solution really. Because the datetime.now() result is the same type as the result of timedelta, it happily adds the two together.

Answer 27

JavaScript, 38 Bytes

d=new Date;d.setDate(d.getDate()+100);d

A little bit shorter than ASCII-only answer.

document.write(eval("d=new Date;d.setDate(d.getDate()+100);d"))

Answer 28

Golang, 58 bytes

import ."time"
func f(){Println(Now().AddDate(0, 0, 100))}

Full Program

package main

import . "time"
import . "fmt"

func main() {
    Println(Now().AddDate(0, 0, 100))
}

try it online!

Answer 29

Oracle, 34 bytes

SELECT CURRENT_DATE+100 FROM DUAL;

Answer 30

Python 2 + Pandas 0.19.1, 56 51 bytes

from pandas import*
print Timestamp('now','D')+100

Answer 31

SAS, 52 bytes

%put%sysfunc(intnx(day,%sysfunc(date()),100),date9.)

Answer 32

R, 16 14 21 bytes

print(Sys.Date()+100)

"2017-07-16"

Answer 33

VBA, 8 bytes

?now+100

output:

2017-07-16 10:13:19 

Works in the Immediate Window. Beats Excel by 2 bytes by skipping parentheses.

Answer 34

JavaScript, 21 bytes

Date(+new Date+864e7)

Actually, you don't really need new before Date.

Based on this post.

document.body.innerHTML = Date(+new Date+864e7);

Answer 35

Perl 6, 20 bytes

print Date.today+100

Try it online!

Answer 36

Pyke, 6 bytes

wVs2h

Try it online! (doesn't use literal because I can't figure out how to embed it)

w      -  get 100 in 2 bytes
  Vs2h - Repeat ^ times
   s2  -   increment the day part
     h -  strip the time part

Hexdump:

77 84 56 73 32 68

Answer 37

AWK, 43 bytes

BEGIN{print strftime("%F",systime()+864e4)}

Could save a few bytes if run using some input... maybe... using something like:

{$0=strftime("%F",systime()+864e4)}1

and running the code like:

awk '{$0=strftime("%F",systime()+864e4)}1'<<<1

But then we have to account for the bytes used to do that. So I'll stick with simplicity :)

Answer 38

VBScript, 18 bytes

dateadd(d,100,now)

Answer 39

k6 and q, 8 bytes

.z.d+100

Apparently, .z.d returns the current date, and the default units when adding to dates are days.

Answer 40

Wolfram Language, 19 bytes

DatePlus[Today,100]

Kinda self-explanatory but let's explain.

DatePlus (From Wolfram Language Reference)

DatePlus[date,{n,"unit"}] gives the date n units after date.

Possible offset units are "Year", "Quarter", "Month", "Week", "Day", "Hour", "Minute", "Second", "Weekday", "Weekend", Monday through Sunday, "EndOfMonth", and "BusinessDay".

Offsets can also be specified using the Quantity framework.

{y,m,d} is taken to be equivalent to {y,m,d,0,0,0} etc.

DatePlus[date,offset] gives results in the same general format as date.

When date is a list, the result has the same length as date, possibly extended to include the smallest unit in offset. »

When date is a string, the result is in the form specified by $DateStringFormat.

Today (From Wolfram Language Reference)

Today
gives a DateObject representing the current day.

So basically, it just adds 100 days to the current date. See screenshot below.

Answer 41

Matlab/Octave, 16 bytes

datestr(now+100)

Pretty much self-explanatory and (a bit) boring, but could not be missing!

Answer 42

NodeJS, 96 bytes

require('http').createServer(function(q,s){s.end(':'+new Date(Date.now()+(864e7)))}).listen(8e3)

My first codegolf attempt ever, but I can't find anything to make it shorter.