Letters in phone numbers

Question

Problem:

You are making a new phone where people can type in specialized phone numbers, for example, 1-800-program, and they would be converted automatically to a usable phone number, like 1-800-7764726 (for the previous example).

Your program will recieve a string if any length with numbers, letters and dashes, and convert all the letters to their corresponding numbers.

Here is a keypad, for reference:

Rules:

• Your program will receive a string
• It will process it and return/print another string
• Any language is accepted
• Since it is code-golf, the shortest code wins

Answer 1

GolfScript, 24 chars

{.96>{,91,'qx'+-,3/`}*}%

Test input:

0123456789-abcdefghijklmnopqrstuvwxyz

Test output:

0123456789-22233344455566677778889999

Explanation:

• { }% applies the code between the braces to each character of the input.

• .96>{ }* executes the code between the inner braces if and only if the ASCII code of the character is greater than 96 (i.e. it is a lowercase letter).

• The first , turns the character into a list of all characters with lower ASCII codes, and 91,'qx'+- filters out all characters with ASCII codes less than 91, as well as the letters q and x, from the list. Thus, for example, the character a gets turned into the 6-character list [\]^_`, while z gets turned into the 29-character list [\]^_`abcdefghijklmnoprstuvwy.

• The second , counts the elements remaining in the list, and 3/ divides this count by three (rounding down). Finally, the ` turns the resulting number (in the range 2 – 9) into a string.

Thus, as per spec, hyphens and numbers are left unchanged, while lowercase letters are mapped into numbers according to the reference keypad diagram. The code will actually cleanly pass through all printable ASCII characters except for lowercase letters (which as mapped as described) and the characters {, | and } (which are mapped to the two-character string 10). Non-ASCII 8-bit input will produce all sorts of weird numeric output.

After all this, it's a bit disappointing that this only beats the trivial bash solution by just six chars.

Answer 2

Bash, 30

Edit: Thank you Doorknob for eliminating 3 chars

tr a-z 22233344455566677778889

Example:

Answer 3

C, 83 78 77 65 63 62

main(c){for(;~(c=getchar());putchar(c>96?20-c/122+5*c/16:c));}

http://ideone.com/qMsIFQ

Answer 4

Javascript - 103 characters

alert(prompt().replace(/[a-z]/g,function(y){y=y.charCodeAt(0)-91;return y>27?9:y>24?8:y>20?7:~~(y/3)}))

Answer 5

Ruby, 75 chars

gets.chars{|c|$><<"22233344455566677778889999#{c}"[[*?a..?z].index(c)||-1]}

Uses the deprecated chars with block, and prints each letter individually with $><<. I also like [[*?a..?z].index(c)||-1]; it grabs the character corresponding to that letter of the alphabet if it's a letter, and the last character (which happens to be the test character unchanged) if not.

Ruby, 43 (or 35) chars

Blatantly stealing from @ace ;)

puts gets.tr'a-z','22233344455566677778889'

Shave off 8 chars if I can run in IRB with the variable s as the string:

s.tr'a-z','22233344455566677778889'

Answer 6

C++ - 222 chars

Longest solution so far:

#include<iostream>
#include<string>
#define o std::cout<<
int main(){std::string s;std::cin>>s;for(int i=0;i<s.size();i++){int j=s[i]-97;if(j<0)o s[i];if(0<=j&j<15)o 2+j/3;if(14<j&j<19)o 7;if(18<j&j<22)o 8;if(21<j&j<26)o 9;}}

Answer 7

Frink, 92

A rather verbose language, I know. This checks 8 values instead of 26 without having to type out the compares. Can any of the above "222333444.." solutions be reduced in a similar way?

Using built in structures, 107

co=new OrderedList
co.insertAll[charList["cfilosv{"]]
println[input[""]=~%s/([a-z])/co.binarySearch[$1]+2/eg]

Using a custom recursive function, 92

fn[x,a]:=x<=(charList["cfilosv{"])@a?a+2:fn[x,a+1]
println[input[""]=~%s/([a-z])/fn[$1,0]/eg]

Answer 8

Smalltalk, 79 70

input is s:

s collect:[:c|' 22233344455566677778889999'at:1put:c;at:(($ato:$z)indexOf:c)+1]

probably not a candidate for being shortest - but may be of interest for an old trick to avoid a test for a not-found condition (indexOf: returns 0 in this case). So no special test for letters is needed. Some Smalltalks however, have immutable strings, and we need 4 more chars ("copy").

Oh, a better version, which even deals with immutable strings in 70 chars:

s collect:[:c|c,'22233344455566677778889999'at:(($ato:$z)indexOf:c)+1]

Answer 9

Mathematica 90

This follows the logic of @ace's solution:

StringReplace[#,Thread[CharacterRange["A","Z"]->Characters@"22233344455566677778889999"]]&

Example

StringReplace[#1,Thread[CharacterRange["A","Z"]-> 
Characters@"22233344455566677778889999"]]&["VI37889"]

8437889

Answer 10

Perl, 50

Another obvious copy of Ace's bash answer

($_)=@ARGV;y/a-z/22233344455566677778889999/;print

Answer 11

PHP, 141

Not the shortest, but more fun:

<?php foreach(str_split($argv[1])as$c){$v=ord($c);if($v>114){$v--;}if($v==121){$v--;}if($v<123&$v>96){echo chr(ceil($v/3+17));}else{echo$c;}}

More readable:

<?php 
foreach (str_split($argv[1]) as $c) {
  $v=ord($c);
  if ($v>114) {$v--;}
  if ($v==121){$v--;}
  if ($v<123 & $v>96){
    echo chr(ceil($v/3+17));
    } else {echo $c;}
}

Answer 12

R, very long but fun

foo <- '1-800-splurghazquieaobuer57'
oof <- unlist(strsplit(foo,''))
#don't count that part - it's input formatting :-) 
digout <- unlist(strsplit('22233344455566677778889999','')) 
oof[oof%in%letters[1:26]] <- unlist(sapply(oof[oof%in%letters[1:26]], function(j) digout[which(letters[1:26]==j)] ))

Answer 13

k [32 Chars]

{(.Q.a!|,/(4 3 4,5#3)#'|$2+!8)x}

Usage

{(.Q.a!|,/(4 3 4,5#3)#'|$2+!8)x}"stack exchange"
"78225 39242643"

Answer 14

JavaScript, 85

JavaScript is never going to win the golf wars, but I like it and I wanted to do something different than jump on the @ace bandwagon.

alert(prompt().replace(/[a-z]/g,function(a){for(i=7;a<"dgjmptw{"[i--];);return i+4}))

Answer 15

Python 2.7, 80

for c in raw_input():print'\b'+(`(ord(c)-97)/3+2-(c in('svyz'))`if c>'`'else c),

I am new to python, so I'm sure there must be a way to golf this even further, it's a different aproach, hope you guys like it, my god, is python pretty!

Run example:

• input: 01-800-abcdefghijklmnopqrstuvwxyz
• output: 01-800-22233344455566677778889999

Answer 16

T-SQL, 216 bytes

I spent quite some time over the past couple of nights painstakingly creating a mathematical sequence function that would round correctly to generate the proper ASCII codes for the numbers from the alphabetical ASCII codes. It had a ridiculous number of decimal places in the coefficients, but it worked.

However, mattnewport's rational approach works in SQL as well, at a much lower cost of bytes, so I am shamelessly scrapping my own math in favor of his. Go up-vote him, it's an elegant solution!

Here's mine:

DECLARE @p VARCHAR(MAX)='';WITH t AS(SELECT ASCII(LEFT(@s,1))c,2 i UNION ALL SELECT ASCII(SUBSTRING(@s,i,1)),i+1FROM t WHERE i<=LEN(@s))SELECT @p=@p+CHAR(CASE WHEN c>96THEN 20-c/122+5*c/16 ELSE c END)FROM t;SELECT @p

This uses a recursive CTE to make an impromptu stack of the characters in the phone number and translate the letters on the fly, then a bit of SQL trickery (SELECT @p=@p+columnValue) to recompose the string from the CTE without requiring another recursion construct.

Output:

DECLARE @s VARCHAR(MAX)='1-800-abcdefghijklmnopqrstuvwxyz'
--above code runs here
1-800-22233344455566677778889999

Answer 17

Python 2.7, 66 65

Anakata's Original

for c in raw_input():print'\b'+(`(ord(c)-97)/3+2-(c in('svyz'))`if c>'`'else c),

Further golfed

for c in input():print(ord(c)-91)/3-(c in('svyz'))if c>'`'else c,

I don't have enough reputation to comment on @anakata's answer, so I made a separate post here. I had the same idea (taking the ordinance modulus 3) but couldn't figure out how to print the right numbers for s - z.

Anyways, the golf improvements I made:

• changed raw_input to input

• removed the extraneous '\b' and parentheses and single quotes

• removed the +2 offset and placed that in the original subtraction (97 - (3 * 2) = 91)

Tested with the Python 2.7.6 interpreter. Assumes, per the rules, a string input.

Answer 18

PHP, 87

echo str_ireplace(range('a','z'),str_split('22233344455566677778889999'),fgets(STDIN));

Answer 19

q [38 Chars]

{(.Q.a!"22233344455566677778889999")x}

Inspired by @ace's solution

Example

{(.Q.a!"22233344455566677778889999")x}"stack exchange"
"78225 39242643"

Answer 20

C# 140

using System.Linq;class P{static void Main(string[]a){System.Console.Write(string.Concat(a[0].Select(d=>(char)(d>96?20-d/122+5*d/16:d))));}}

Answer 21

XQuery, 71

BaseX was used as XQuery processor. $i is input.

translate($i,"abcdefghijklmnopqrstuvwxyz","22233344455566677778889999")

Not the shortest answer, but quite short and very readable.

Answer 22

Python, very ungolfed

Since everyone is copying ace, i decided to post the code i made up before i submitted the question:

def phonekeypad(text):
    c = ['','','abc','def','ghi','jkl','mno','pqrs','tuv','wxyz']
    st = ""
    for i in list(text):
        a = False
        for t in range(len(c)):
            if i in c[t]:
                st += str(t)
                a=True
        if a == False:
            st += str(i)
    return st

Answer 23

EcmaScript 6 (103 bytes):

i.replace(/[a-z]/g,x=>keys(a='00abc0def0ghi0jkl0mno0pqrs0tuv0wxyz'.split(0)).find(X=>a[X].contains(x)))

Expects i to contain the string.

Try it in any recent version of Firefox. I've not tried Google Chrome.

Answer 24

Python 3, 121

print("".join((lambda x:"22233344455566677778889999"[ord(x)-97] if ord(x)>96 and ord(x)<123 else x)(i) for i in input()))

Answer 25

Haskell, 93C

t[]_ a=a
t(b:c)(d:e)a
 |a==b=d
 |True=t c e a
y=map(t['a'..'z']"22233344455566677778889999")

Usage

y "1-800-program"

Answer 26

05AB1E, 11 bytes

Aā6+žq÷T9:‡

Try it online!

A                 # alphabet: "abcdefghijklmnoqrstuvwxyz"
 ā                # length range: [1..26]
  6+              # add 6 to each: [7..32]
    žq÷           # divide by pi: [2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,10]
       T9:        # replace 10 with 9
          ‡       # transliterate the input (a => 2, ..., z => 9)

Answer 27

Python

import string          
trans = str.maketrans(string.ascii_lowercase,
                      '22233344455566677778889999')                                                                                         
print("1-800-ask-usps".translate(trans))

Answer 28

ECMASCRIPT, 101 (with input)

"1-800-PROGRAM".replace(/./g,function(c){
return "22233344455566677778889999"[c.charCodeAt(0)-65]||c})

Newline added for clarity. 85 characters if the input is in a variable.

Answer 29

Perl, 54

print map{/[a-y]/?int(5/16*ord)-28:/z/?9:$_}<>=~/./gs

Shoot, @RobHoare still beat me by 4 characters. :)

Answer 30

QBasic, 155

Ah, the memories...

INPUT n$
FOR i=1 TO LEN(n$)
c$=MID$(n$,i,1)
a=ASC(c$)
IF 97>a THEN
PRINT c$;
ELSE IF 122>a THEN
PRINT STR$(a\3.2-28);
ELSE
PRINT 9;
END IF
NEXT i

This should have been shorter, but I was testing with repl.it, which doesn't allow single-line IF statements and behaves strangely if you leave the variable off of NEXT i. It also doesn't recognize the ASC function, so to run the code you'll need to add this workaround at the beginning:

DECLARE FUNCTION ASC(s$)
FUNCTION ASC(s$)
FOR j=1 TO 255
IF CHR$(j)=LEFT$(s$,1) THEN
ASC=j
END IF
NEXT j
END FUNCTION

(The second time you run it, the interpreter will complain unless you remove the DECLARE FUNCTION line, go figure.)

Answer 31

R, 110

s=strsplit(scan(,""),"")[[1]];i=grep("[a-z]",s);s[i]=sort(c(1:24%%8+2,7,9))[match(s[i],letters)];cat(s,sep="")

Example:

> s=strsplit(scan(,""),"")[[1]];i=grep("[a-z]",s);s[i]=sort(c(1:24%%8+2,7,9))[match(s[i],letters)];cat(s,sep="")
1: 1-800-program
2: 
Read 1 item
1-800-7764726

Answer 32

VB.net (61c)

Excludes the 45c min for a valid vb.net program.

Module P
Sub Main(A()As string)
For Each x In A(0).ToUpper 
Console.Write(If(x<"A"or x>"Z",x,Chr(Asc(x)\4+35)))
Next
End Sub
End Module