Acrostic Poem - Programming

Question

TASK:

Make an acrostic poem in the lines.
e.g.

BATCH

break  
attrib -h acrostic.txt  
type acrostic.txt  
cls  
help 

The output CAN also be an acrostic poem.

RULES:

• Popularity Contest - the answer with highest vote wins!
• You may create more than one.
• Any language is accepted.
• Every line must be executable.

Answer 1

Java

class s {
//acrostic starts below this line  
public static void main(String[] args) { int
a; int
n;
class b {}
a=1; int 
k; int
e;
System.out.println("are very tasteful."); } }

Answer 2

bash - every man dies alone

This line writes the poem:

echo echo view echo renice yes make apropos nice date identify echo start apropos locate octave nice echo | xargs -n 1 | awk '{s = s substr($1, 1, 1); if ($1 == "echo"){print $1, "-n", s; s = "";}else print $1, "--they >.said 2>&1";}' > acrostic.sh

To see the poem:

$ cat acrostic.sh

To see the poem within the poem:

$ sh acrostic.sh

Answer 3

Batch

Quite lazy, I'll admit -

@(
Code
Other than that which
Does
Echo Code^
Golf
Often
Lacks the
Fun
) 2>nul

H:\uprof>accro.bat
CodeGolf

Answer 4

Yay! Java!

import java.io.*;public
class poem{static String[]
a = 
new String[1];
public static void main(String[] args){a();fin();
return;}static
Object myMethod(){String
g = "This is my ";
return g;} static void a(){
a[0] = "output";}static boolean fin(){System.out.println(
myMethod().toString()+a[0]);Boolean fin =
!(0==1);return fin;}}

Answer 5

Befunge-93

go down, "Dev" 00ps -- 2*4-10 \ please
um I guess 1 - 3 \, is that right "hmm", @
maybe

run as ./befungee.py acrostic for the output gum.

Note sure how rule #3 should be interpreted in this context.

Answer 6

Ruby

ruby = "rubylicious"; control = true
unless (!ruby)
begin y = ruby
y.each_char do |l| print (
l)
if (l=='s') then 
control=false end  
if (!control) then puts "!" end
over = true
unless 
self == true then over = false end end end end

This prints Rubylicious!. I am not happy with some of the lines (especially last line), so future edits are possible.

Answer 7

Javascript

document.getElementById("dog).appendChild(document.createElement('div'));
o = [];
e = [];
s = [];

t = 0;
h = 0;
i = 0;
s[0] = 0;

e[0] = 0;
v = 0;
e[1] = 0;
n = [];

c = 0;
o[0] = 0;
u = 0;
n[0] = 0;
t
? count=1:count=0;